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If the probability that the Islanders will beat the Rangers in a game is 
67%, what is the probability that the Islanders will win at least four out of seven games in a series against the Rangers? Round your answer to the nearest thousandth.
Answer:

If the probability that the Islanders will beat the Rangers in a game is 67% 67 \% , what is the probability that the Islanders will win at least four out of seven games in a series against the Rangers? Round your answer to the nearest thousandth.\newlineAnswer:

Full solution

Q. If the probability that the Islanders will beat the Rangers in a game is 67% 67 \% , what is the probability that the Islanders will win at least four out of seven games in a series against the Rangers? Round your answer to the nearest thousandth.\newlineAnswer:
  1. Understand the problem: Understand the problem and determine the approach.\newlineWe need to calculate the probability of the Islanders winning at least 44 out of 77 games. This is a binomial probability problem because each game has two outcomes (win or lose), and we want to find the probability of a certain number of wins in a fixed number of trials (games).
  2. Calculate wins probability: Calculate the probability of winning exactly 44, 55, 66, and 77 games.\newlineWe will use the binomial probability formula: P(X=k)=C(n,k)pk(1p)nkP(X = k) = C(n, k) \cdot p^k \cdot (1-p)^{n-k}, where:\newline- P(X=k)P(X = k) is the probability of kk wins,\newline- C(n,k)C(n, k) is the combination of nn games taken kk at a time,\newline- 5500 is the probability of winning one game (5511 or 5522),\newline- nn is the total number of games (77),\newline- kk is the number of games won (which we will calculate for 44, 55, 66, and 77).
  3. Calculate 44 games probability: Calculate the probability of winning exactly 44 games.\newlineUsing the binomial formula, we find P(X=4)P(X = 4):\newlineC(7,4)0.674(10.67)74C(7, 4) \cdot 0.67^4 \cdot (1-0.67)^{7-4}\newline=350.6740.333= 35 \cdot 0.67^4 \cdot 0.33^3\newline=350.201511210.035937= 35 \cdot 0.20151121 \cdot 0.035937\newline=350.007237= 35 \cdot 0.007237\newline0.2533\approx 0.2533
  4. Calculate 55 games probability: Calculate the probability of winning exactly 55 games. Using the binomial formula, we find P(X=5)P(X = 5): C(7,5)0.675(10.67)75C(7, 5) \cdot 0.67^5 \cdot (1-0.67)^{7-5} = 210.6750.33221 \cdot 0.67^5 \cdot 0.33^2 = 210.132079340.108921 \cdot 0.13207934 \cdot 0.1089 = 210.01437921 \cdot 0.014379 0.3019\approx 0.3019
  5. Calculate 66 games probability: Calculate the probability of winning exactly 66 games.\newlineUsing the binomial formula, we find P(X=6)P(X = 6):\newlineC(7,6)0.676(10.67)(76)C(7, 6) \cdot 0.67^6 \cdot (1-0.67)^{(7-6)}\newline=70.6760.331= 7 \cdot 0.67^6 \cdot 0.33^1\newline=70.088038340.33= 7 \cdot 0.08803834 \cdot 0.33\newline=70.029046= 7 \cdot 0.029046\newline0.2033\approx 0.2033
  6. Calculate 77 games probability: Calculate the probability of winning all 77 games.\newlineUsing the binomial formula, we find P(X=7)P(X = 7):\newlineC(7,7)×0.677×(10.67)(77)C(7, 7) \times 0.67^7 \times (1-0.67)^{(7-7)}\newline=1×0.677×0.330= 1 \times 0.67^7 \times 0.33^0\newline=1×0.06706822×1= 1 \times 0.06706822 \times 1\newline=0.06706822= 0.06706822\newline0.0671\approx 0.0671
  7. Calculate total probability: Add the probabilities of winning exactly 44, 55, 66, and 77 games to find the total probability of winning at least 44 games.\newlineTotal probability = P(X=4)+P(X=5)+P(X=6)+P(X=7)P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)\newline0.2533+0.3019+0.2033+0.0671\approx 0.2533 + 0.3019 + 0.2033 + 0.0671\newline0.8256\approx 0.8256
  8. Round total probability: Round the total probability to the nearest thousandth. Rounded probability = 0.8260.826

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