Q. If h(w)=19w2−38w−2, use synthetic division to find h(1).
Set up synthetic division: First, set up the synthetic division with 1 as the root we're testing and the coefficients of h(w) in descending order of w.
Bring down first coefficient: The synthetic division setup looks like this:1∣19−38−2Now, bring down the 19 to the bottom row.
Multiply and write result: Multiply 1 by 19 and write the result under the next coefficient:1∣19−38−2\,\,|\,\underline{\quad\quad\quad\quad}\,\,|\, 19 \,\, 19
Add numbers in second column: Add the numbers in the second column:−38+19=−19Write this sum in the bottom row.1∣19−38−2 |_______ | 19−19
Multiply and write result: Multiply 1 by −19 and write the result under the next coefficient:1∣19−38−2\phantom{1 \,|\,}_______191∣19−19−19
Add numbers in third column: Add the numbers in the third column:−2+(−19)=−21Write this sum in the bottom row.1∣19−38−2 |_______19−19 | 19−19−21
Find remainder: The number in the bottom right is the remainder, which represents h(1).
More problems from Evaluate polynomials using synthetic division