Q. If h(u)=11u2−38u−23, use synthetic division to find h(4).
Set up synthetic division: Set up the synthetic division by writing down the coefficients of h(u) and the value we are evaluating, which is 4. Coefficients: 11, −38, −23 Value to evaluate: 4
Bring down leading coefficient: Begin synthetic division. Bring down the leading coefficient, which is 11.
Multiply and add: Multiply the value we brought down (11) by 4 and write the result under the next coefficient (−38).11×4=44
Repeat multiplication and addition: Add the result 44 to the next coefficient −38 to get the new coefficient.−38+44=6
Find the remainder: Multiply the new coefficient (6) by 4 and write the result under the next coefficient (−23).6×4=24
Find the remainder: Multiply the new coefficient 6 by 4 and write the result under the next coefficient −23.6×4=24 Add the result 24 to the next coefficient −23 to get the new coefficient.−23+24=1
Find the remainder: Multiply the new coefficient 6 by 4 and write the result under the next coefficient −23.6×4=24 Add the result 24 to the next coefficient −23 to get the new coefficient.−23+24=1 The last number obtained 1 is the remainder, which represents the value of h(4).
More problems from Evaluate polynomials using synthetic division