If g(v) = 9v^2 - 20v + 9, use synthetic division to find g(1). ____

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Write Coefficients and Value: To use synthetic division, we first write down the coefficients of the polynomial and the value we are evaluating, which is 1. Coefficients: 9, -20, 9 Value to evaluate: 1Set Up Synthetic Division: Set up the synthetic division by placing the value to evaluate outside the division box and the coefficients inside.   _______ 1 | 9  -20  9Bring Down Coefficient: Bring down the first coefficient, which is 9, to the bottom row.   _______ 1 | 9  -20  9      -----------        9Multiply and Write Result: Multiply the value we brought down (9) by the value we are evaluating (1) and write the result under the next coefficient.   _______ 1 | 9  -20  9      9      -----------        9Add Result to Next Coefficient: Add the result of the multiplication (9) to the next coefficient (-20) and write the sum below.   _______ 1 | 9  -20  9      9  -11      -----------        9Multiply and Write Result: Multiply the sum we just found (-11) by the value we are evaluating (1) and write the result under the next coefficient.   _______ 1 | 9  -20  9      9  -11      -11      -----------        9Add Result to Next Coefficient: Add the result of the multiplication (-11) to the next coefficient (9) and write the sum below.   _______ 1 | 9  -20  9      9  -11      -11      -----------        9  -2Find Remainder and Final Answer: The last number in the bottom row is the remainder, which is also the value of g(1). Final answer: g(1) = -2

If $g(v) = 9v^2 - 20v + 9$ , use synthetic division to find $g(1)$ .

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If g(v)=9v2−20v+9g(v) = 9v^2 - 20v + 9g(v)=9v2−20v+9, use synthetic division to find g(1)g(1)g(1).

If $g(v) = 9v^2 - 20v + 9$ , use synthetic division to find $g(1)$ .