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If 
f(x)=(sqrtx+18)/(3x), what is the value of 
f(5), to the nearest tenth (if necessary)?
Answer:

If f(x)=x+183x f(x)=\frac{\sqrt{x}+18}{3 x} , what is the value of f(5) f(5) , to the nearest tenth (if necessary)?\newlineAnswer:

Full solution

Q. If f(x)=x+183x f(x)=\frac{\sqrt{x}+18}{3 x} , what is the value of f(5) f(5) , to the nearest tenth (if necessary)?\newlineAnswer:
  1. Substitute xx with 55: To find the value of f(5)f(5), we need to substitute xx with 55 in the function f(x)=x+183xf(x) = \frac{\sqrt{x} + 18}{3x}.\newlineCalculation: f(5)=5+183×5f(5) = \frac{\sqrt{5} + 18}{3 \times 5}
  2. Simplify numerator: Now we simplify the numerator by calculating the square root of 55 and then adding 1818.\newlineCalculation: 52.236+1820.236\sqrt{5} \approx 2.236 + 18 \approx 20.236
  3. Simplify denominator: Next, we simplify the denominator by multiplying 33 by 55.\newlineCalculation: 3×5=153 \times 5 = 15
  4. Divide numerator by denominator: Now we divide the simplified numerator by the simplified denominator to get the value of f(5)f(5).\newlineCalculation: f(5)20.236151.349f(5) \approx \frac{20.236}{15} \approx 1.349
  5. Round to nearest tenth: Since we need to round the answer to the nearest tenth, we round 1.3491.349 to 1.31.3.\newlineCalculation: Rounded value of f(5)1.3f(5) \approx 1.3

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