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If 
f(x)=7^(4x)-11, what is the value of 
f(1), to the nearest ten-thousandth (if necessary)?
Answer:

If f(x)=74x11 f(x)=7^{4 x}-11 , what is the value of f(1) f(1) , to the nearest ten-thousandth (if necessary)?\newlineAnswer:

Full solution

Q. If f(x)=74x11 f(x)=7^{4 x}-11 , what is the value of f(1) f(1) , to the nearest ten-thousandth (if necessary)?\newlineAnswer:
  1. Substitute xx with 11: To find the value of f(1)f(1), we need to substitute xx with 11 in the function f(x)=74x11f(x) = 7^{4x} - 11.
    f(1)=74×111f(1) = 7^{4\times 1} - 11
    f(1)=7411f(1) = 7^4 - 11
  2. Calculate 747^4: Now we calculate 747^4, which is 77 multiplied by itself 44 times.\newline74=7×7×7×77^4 = 7 \times 7 \times 7 \times 7\newline74=24017^4 = 2401
  3. Subtract 1111: Subtract 1111 from 24012401 to get the value of f(1)f(1). \newlinef(1)=240111f(1) = 2401 - 11\newlinef(1)=2390f(1) = 2390
  4. No rounding needed: The question asks for the answer to the nearest ten-thousandth, but since our result is an integer, no rounding is necessary.\newlinef(1)=2390f(1) = 2390

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