Q. If f(x)=3x−1 and g(x)=x2+1, what is the value of g(f(3)) ?Choose 1 answer:(A) 8(B) 10(C) 29(D) 65
Find f(3): First, we need to find the value of f(3) by substituting x with 3 in the function f(x). f(x)=3x−1 f(3)=3(3)−1 f(3)=9−1 f(3)=8
Calculate g(f(3)): Now that we have f(3)=8, we need to find the value of g(f(3)) by substituting f(3) into the function g(x). g(x)=x2+1 g(f(3))=g(8)=82+1 g(f(3))=64+1 g(f(3))=65
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