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Let’s check out your problem:
If
f
′
(
x
)
=
1
/
f
(
x
)
f^{\prime}(x)=1 / f(x)
f
′
(
x
)
=
1/
f
(
x
)
and
f
(
0
)
=
2
f(0)=2
f
(
0
)
=
2
, then
f
(
4
)
f(4)
f
(
4
)
can be written in fully simplified form as
m
n
m \sqrt{n}
m
n
for some
integers
m
m
m
and
n
n
n
.
\newline
What are
m
m
m
and
n
n
n
?
\newline
m
=
□
n
=
□
\begin{array}{l} m= \square \\ n= \square \end{array}
m
=
□
n
=
□
View step-by-step help
Home
Math Problems
Algebra 1
Negative exponents
Full solution
Q.
If
f
′
(
x
)
=
1
/
f
(
x
)
f^{\prime}(x)=1 / f(x)
f
′
(
x
)
=
1/
f
(
x
)
and
f
(
0
)
=
2
f(0)=2
f
(
0
)
=
2
, then
f
(
4
)
f(4)
f
(
4
)
can be written in fully simplified form as
m
n
m \sqrt{n}
m
n
for some integers
m
m
m
and
n
n
n
.
\newline
What are
m
m
m
and
n
n
n
?
\newline
m
=
□
n
=
□
\begin{array}{l} m= \square \\ n= \square \end{array}
m
=
□
n
=
□
Identify Given and Asked:
Identify the given information and what is asked.
\newline
Given:
f
′
(
x
)
=
1
f
(
x
)
f'(x) = \frac{1}{f(x)}
f
′
(
x
)
=
f
(
x
)
1
and
f
(
0
)
=
2
f(0) = 2
f
(
0
)
=
2
.
\newline
Asked:
f
(
4
)
f(4)
f
(
4
)
in the form of
m
n
m\sqrt{n}
m
n
.
Recognize Exponential Function:
Recognize that
f
′
(
x
)
=
1
f
(
x
)
f^{\prime}(x) = \frac{1}{f(x)}
f
′
(
x
)
=
f
(
x
)
1
suggests that
f
(
x
)
f(x)
f
(
x
)
is an exponential function.
\newline
Assume
f
(
x
)
=
a
x
f(x) = a^{x}
f
(
x
)
=
a
x
, then
f
′
(
x
)
=
ln
(
a
)
⋅
a
x
f^{\prime}(x) = \ln(a) \cdot a^{x}
f
′
(
x
)
=
ln
(
a
)
⋅
a
x
.
Equation Simplification:
Since
f
′
(
x
)
=
1
f
(
x
)
f^{'}(x) = \frac{1}{f(x)}
f
′
(
x
)
=
f
(
x
)
1
, we have
ln
(
a
)
⋅
a
x
=
1
a
x
\ln(a) \cdot a^{x} = \frac{1}{a^{x}}
ln
(
a
)
⋅
a
x
=
a
x
1
. This implies
ln
(
a
)
=
1
a
2
x
\ln(a) = \frac{1}{a^{2x}}
ln
(
a
)
=
a
2
x
1
.
Find Base from Initial Condition:
Use the initial condition
f
(
0
)
=
2
f(0) = 2
f
(
0
)
=
2
to find the base
a
a
a
.
f
(
0
)
=
a
0
=
2
f(0) = a^{0} = 2
f
(
0
)
=
a
0
=
2
, so
a
=
2
a = 2
a
=
2
.
Calculate
f
(
4
)
f(4)
f
(
4
)
:
Now we know
f
(
x
)
=
2
x
f(x) = 2^{x}
f
(
x
)
=
2
x
.
\newline
To find
f
(
4
)
f(4)
f
(
4
)
, calculate
2
4
2^{4}
2
4
.
\newline
f
(
4
)
=
2
4
=
16
f(4) = 2^{4} = 16
f
(
4
)
=
2
4
=
16
.
Express in
m
n
m\sqrt{n}
m
n
:
Express
16
16
16
in the form of
m
n
m\sqrt{n}
m
n
.
16
=
4
×
4
=
4
×
4
=
4
4
16 = 4 \times 4 = 4 \times \sqrt{4} = 4\sqrt{4}
16
=
4
×
4
=
4
×
4
=
4
4
.So,
m
=
4
m = 4
m
=
4
and
n
=
4
n = 4
n
=
4
.
More problems from Negative exponents
Question
Order the expressions from least to greatest.
\newline
5
2
4
2
+
2
2
6
2
−
6
5^{2} \quad 4^{2}+2^{2} \quad 6^{2}-6
5
2
4
2
+
2
2
6
2
−
6
Get tutor help
Posted 10 months ago
Question
Evaluate the expression. Do not round your answer.
\newline
1
5
(
3
+
2
+
5
)
2
=
\frac{1}{5}(3+2+5)^{2}=
5
1
(
3
+
2
+
5
)
2
=
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Posted 10 months ago
Question
Evaluate the expression.
\newline
Do not round your answer.
\newline
5
−
3
2
2
=
5-\frac{3^{2}}{2}=
5
−
2
3
2
=
Get tutor help
Posted 10 months ago
Question
Evaluate the following expression.
\newline
8
3
−
9
⋅
2
÷
3
=
8^{3}-9 \cdot 2 \div 3=
8
3
−
9
⋅
2
÷
3
=
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Posted 10 months ago
Question
Evaluate the expression. Do not round your answer.
\newline
1
4
(
6
+
3
+
1
)
2
=
\frac{1}{4}(6+3+1)^{2}=
4
1
(
6
+
3
+
1
)
2
=
Get tutor help
Posted 10 months ago
Question
Evaluate the expression. Do not round your answer.
\newline
(
2
⋅
3
)
2
+
5
2
=
(2 \cdot 3)^{2}+5^{2}=
(
2
⋅
3
)
2
+
5
2
=
Get tutor help
Posted 10 months ago
Question
Evaluate the expression. Do not round your answer.
\newline
1
3
(
4
⋅
3
)
+
2
3
=
\frac{1}{3}(4 \cdot 3)+2^{3}=
3
1
(
4
⋅
3
)
+
2
3
=
Get tutor help
Posted 10 months ago
Question
Evaluate the expression.
\newline
Do not round your answer.
\newline
2
(
3
2
+
4
2
)
=
2\left(3^{2}+4^{2}\right)=
2
(
3
2
+
4
2
)
=
Get tutor help
Posted 10 months ago
Question
Evaluate.
\newline
2
×
10
−
7
×
2
=
2 \times 10-7 \times 2=
2
×
10
−
7
×
2
=
Get tutor help
Posted 10 months ago
Question
−
1.2
−
29
20
=
-1.2-\frac{29}{20}=
−
1.2
−
20
29
=
\newline
Enter the answer as an exact decimal or simplified fraction.
Get tutor help
Posted 9 months ago
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