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If 
f^(')(x)=1//f(x) and 
f(0)=2, then 
f(4) can be written in fully simplified form as 
msqrtn for some integers 
m and 
n.
What are 
m and 
n ?

{:[m=],[n=]:}

If f(x)=1/f(x) f^{\prime}(x)=1 / f(x) and f(0)=2 f(0)=2 , then f(4) f(4) can be written in fully simplified form as mn m \sqrt{n} for some integers m m and n n .\newlineWhat are m m and n n ?\newlinem=n= \begin{array}{l} m= \square \\ n= \square \end{array}

Full solution

Q. If f(x)=1/f(x) f^{\prime}(x)=1 / f(x) and f(0)=2 f(0)=2 , then f(4) f(4) can be written in fully simplified form as mn m \sqrt{n} for some integers m m and n n .\newlineWhat are m m and n n ?\newlinem=n= \begin{array}{l} m= \square \\ n= \square \end{array}
  1. Identify Given and Asked: Identify the given information and what is asked.\newlineGiven: f(x)=1f(x)f'(x) = \frac{1}{f(x)} and f(0)=2f(0) = 2.\newlineAsked: f(4)f(4) in the form of mnm\sqrt{n}.
  2. Recognize Exponential Function: Recognize that f(x)=1f(x)f^{\prime}(x) = \frac{1}{f(x)} suggests that f(x)f(x) is an exponential function.\newlineAssume f(x)=axf(x) = a^{x}, then f(x)=ln(a)axf^{\prime}(x) = \ln(a) \cdot a^{x}.
  3. Equation Simplification: Since f(x)=1f(x)f^{'}(x) = \frac{1}{f(x)}, we have ln(a)ax=1ax\ln(a) \cdot a^{x} = \frac{1}{a^{x}}. This implies ln(a)=1a2x\ln(a) = \frac{1}{a^{2x}}.
  4. Find Base from Initial Condition: Use the initial condition f(0)=2f(0) = 2 to find the base aa.f(0)=a0=2f(0) = a^{0} = 2, so a=2a = 2.
  5. Calculate f(4)f(4): Now we know f(x)=2xf(x) = 2^{x}.\newlineTo find f(4)f(4), calculate 242^{4}.\newlinef(4)=24=16f(4) = 2^{4} = 16.
  6. Express in mnm\sqrt{n}: Express 1616 in the form of mnm\sqrt{n}.16=4×4=4×4=4416 = 4 \times 4 = 4 \times \sqrt{4} = 4\sqrt{4}.So, m=4m = 4 and n=4n = 4.

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