If f(1)=9 and f(n)=f(n-1)+3 then find the value of f(4). Answer:

Initialize f(1): We are given that f(1) = 9. To find f(4), we need to apply the recursive formula f(n) = f(n-1) + 3 three times, starting from n = 2 up to n = 4.Calculate f(2): First, let's find f(2). According to the recursive formula, f(2) = f(2-1) + 3 = f(1) + 3. We know that f(1) = 9, so f(2) = 9 + 3 = 12.Find f(3): Next, we find f(3). Using the recursive formula again, f(3) = f(3-1) + 3 = f(2) + 3. We have already found that f(2) = 12, so f(3) = 12 + 3 = 15.Compute f(4): Finally, we calculate f(4). Using the recursive formula once more, f(4) = f(4-1) + 3 = f(3) + 3. We have found that f(3) = 15, so f(4) = 15 + 3 = 18.

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If
f(1)=9 and
f(n)=f(n-1)+3 then find the value of
f(4).
Answer:

If $f(1)=9$ and $f(n)=f(n-1)+3$ then find the value of $f(4)$ . $\newline$ Answer:

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Precalculus

Find the roots of factored polynomials

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Q. If

f(1)=9

and

f(n)=f(n-1)+3

then find the value of

f(4)

\newline

Answer:

Initialize $f(1)$ : We are given that $f(1) = 9$ . To find $f(4)$ , we need to apply the recursive formula $f(n) = f(n-1) + 3$ three times, starting from $n = 2$ up to $n = 4$ .
Calculate $f(2)$ : First, let's find $f(2)$ . According to the recursive formula, $f(2) = f(2-1) + 3 = f(1) + 3$ . We know that $f(1) = 9$ , so $f(2) = 9 + 3 = 12$ .
Find $f(3)$ : Next, we find $f(3)$ . Using the recursive formula again, $f(3) = f(3-1) + 3 = f(2) + 3$ . We have already found that $f(2) = 12$ , so $f(3) = 12 + 3 = 15$ .
Compute $f(4)$ : Finally, we calculate $f(4)$ . Using the recursive formula once more, $f(4) = f(4-1) + 3 = f(3) + 3$ . We have found that $f(3) = 15$ , so $f(4) = 15 + 3 = 18$ .