If f(1)=5,f(2)=2 and f(n)=3f(n-1)+3f(n-2) then find the value of f(4). Answer:

Given Recursive Formula: We are given the recursive formula f(n) = 3f(n-1) + 3f(n-2), and the initial conditions f(1) = 5 and f(2) = 2. To find f(4), we first need to find f(3) using the recursive formula.Calculate f(3): Using the recursive formula, we calculate f(3) as follows: f(3) = 3f(2) + 3f(1) f(3) = 3(2) + 3(5) f(3) = 6 + 15 f(3) = 21 Now we have the value of f(3).Find f(4): Next, we use the values of f(2) and f(3) to find f(4) using the same recursive formula: f(4) = 3f(3) + 3f(2) f(4) = 3(21) + 3(2) f(4) = 63 + 6 f(4) = 69 We have now found the value of f(4).

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If
f(1)=5,f(2)=2 and
f(n)=3f(n-1)+3f(n-2) then find the value of
f(4).
Answer:

If $f(1)=5, f(2)=2$ and $f(n)=3 f(n-1)+3 f(n-2)$ then find the value of $f(4)$ . $\newline$ Answer:

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Precalculus

Find the roots of factored polynomials

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Q. If

f(1)=5, f(2)=2

and

f(n)=3 f(n-1)+3 f(n-2)

then find the value of

f(4)

\newline

Answer:

Given Recursive Formula: We are given the recursive formula $f(n) = 3f(n-1) + 3f(n-2)$ , and the initial conditions $f(1) = 5$ and $f(2) = 2$ . To find $f(4)$ , we first need to find $f(3)$ using the recursive formula.
Calculate $f(3)$ : Using the recursive formula, we calculate $f(3)$ as follows: $\newline$ $f(3) = 3f(2) + 3f(1)$ $\newline$ $f(3) = 3(2) + 3(5)$ $\newline$ $f(3) = 6 + 15$ $\newline$ $f(3) = 21$ $\newline$ Now we have the value of $f(3)$ .
Find $f(4)$ : Next, we use the values of $f(2)$ and $f(3)$ to find $f(4)$ using the same recursive formula: $\newline$ $f(4) = 3f(3) + 3f(2)$ $\newline$ $f(4) = 3(21) + 3(2)$ $\newline$ $f(4) = 63 + 6$ $\newline$ $f(4) = 69$ $\newline$ We have now found the value of $f(4)$ .