If f(1)=4 and f(n)=f(n-1)-5 then find the value of f(4). Answer:

Given f(1) = 4: We are given that f(1) = 4. To find f(4), we need to apply the recursive formula f(n) = f(n-1) - 5 three times, starting with n = 2 and ending with n = 4.Find f(2): First, let's find f(2) using the recursive formula. We know that f(1) = 4, so f(2) = f(1) - 5 = 4 - 5.Calculate f(2): Calculating f(2) gives us f(2) = -1.Find f(3): Next, we find f(3) using the recursive formula. We have f(2) = -1, so f(3) = f(2) - 5 = -1 - 5.Calculate f(3): Calculating f(3) gives us f(3) = -6.Find f(4): Finally, we find f(4) using the recursive formula. We have f(3) = -6, so f(4) = f(3) - 5 = -6 - 5.Calculate f(4): Calculating f(4) gives us f(4) = -11.

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If
f(1)=4 and
f(n)=f(n-1)-5 then find the value of
f(4).
Answer:

If $f(1)=4$ and $f(n)=f(n-1)-5$ then find the value of $f(4)$ . $\newline$ Answer:

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Precalculus

Find the roots of factored polynomials

Full solution

Q. If

f(1)=4

and

f(n)=f(n-1)-5

then find the value of

f(4)

\newline

Answer:

Given $f(1) = 4$ : We are given that $f(1) = 4$ . To find $f(4)$ , we need to apply the recursive formula $f(n) = f(n-1) - 5$ three times, starting with $n = 2$ and ending with $n = 4$ .
Find $f(2)$ : First, let's find $f(2)$ using the recursive formula. We know that $f(1) = 4$ , so $f(2) = f(1) - 5 = 4 - 5$ .
Calculate $f(2)$ : Calculating $f(2)$ gives us $f(2) = -1$ .
Find $f(3)$ : Next, we find $f(3)$ using the recursive formula. We have $f(2) = -1$ , so $f(3) = f(2) - 5 = -1 - 5$ .
Calculate $f(3)$ : Calculating $f(3)$ gives us $f(3) = -6$ .
Find $f(4)$ : Finally, we find $f(4)$ using the recursive formula. We have $f(3) = -6$ , so $f(4) = f(3) - 5 = -6 - 5$ .
Calculate $f(4)$ : Calculating $f(4)$ gives us $f(4) = -11$ .