If f(1)=4 and f(n+1)=f(n)^(2)-4 then find the value of f(3). Answer:

Given initial condition and formula: We are given the initial condition and the recursive formula: f(1) = 4 f(n+1) = f(n)^(2) - 4 We need to find f(3). To do this, we will first find f(2) using the given recursive formula and the initial condition. Substitute n = 1 into the recursive formula to find f(2). f(2) = f(1)^(2) - 4 f(2) = 4^2 - 4 f(2) = 16 - 4 f(2) = 12Find f(2): Now that we have f(2), we can use it to find f(3) using the same recursive formula. Substitute n = 2 into the recursive formula to find f(3). f(3) = f(2)^(2) - 4 f(3) = 12^2 - 4 f(3) = 144 - 4 f(3) = 140

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If
f(1)=4 and
f(n+1)=f(n)^(2)-4 then find the value of
f(3).
Answer:

If $f(1)=4$ and $f(n+1)=f(n)^{2}-4$ then find the value of $f(3)$ . $\newline$ Answer:

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Algebra 2

Evaluate expression when two complex numbers are given

Full solution

Q. If

f(1)=4

and

f(n+1)=f(n)^{2}-4

then find the value of

f(3)

\newline

Answer:

Given initial condition and formula: We are given the initial condition and the recursive formula: $\newline$ $f(1) = 4$ $\newline$ $f(n+1) = f(n)^{2} - 4$ $\newline$ We need to find $f(3)$ . To do this, we will first find $f(2)$ using the given recursive formula and the initial condition. $\newline$ Substitute $n = 1$ into the recursive formula to find $f(2)$ . $\newline$ $f(2) = f(1)^{2} - 4$ $\newline$ $f(2) = 4^2 - 4$ $\newline$ $f(2) = 16 - 4$ $\newline$ $f(2) = 12$
Find $f(2)$ : Now that we have $f(2)$ , we can use it to find $f(3)$ using the same recursive formula. $\newline$ Substitute $n = 2$ into the recursive formula to find $f(3)$ . $\newline$ $f(3) = f(2)^{2} - 4$ $\newline$ $f(3) = 12^{2} - 4$ $\newline$ $f(3) = 144 - 4$ $\newline$ $f(3) = 140$