If f(1)=4 and f(n+1)=f(n)^(2)+3 then find the value of f(4). Answer:

Given initial condition and formula: We are given the initial condition and the recursive formula for the function f: f(1) = 4 f(n+1) = f(n)^(2) + 3 We need to find the value of f(4). We will start by finding f(2) using the given recursive formula. Substitute n=1 into the recursive formula to find f(2). f(2) = f(1)^(2) + 3 f(2) = 4^2 + 3 f(2) = 16 + 3 f(2) = 19Find f(2): Now that we have f(2), we will use it to find f(3). Substitute n=2 into the recursive formula to find f(3). f(3) = f(2)^(2) + 3 f(3) = 19^2 + 3 f(3) = 361 + 3 f(3) = 364Find f(3): Finally, we will use f(3) to find f(4). Substitute n=3 into the recursive formula to find f(4). f(4) = f(3)^(2) + 3 f(4) = 364^2 + 3 f(4) = 132496 + 3 f(4) = 132499

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If
f(1)=4 and
f(n+1)=f(n)^(2)+3 then find the value of
f(4).
Answer:

If $f(1)=4$ and $f(n+1)=f(n)^{2}+3$ then find the value of $f(4)$ . $\newline$ Answer:

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Algebra 2

Evaluate expression when two complex numbers are given

Full solution

Q. If

f(1)=4

and

f(n+1)=f(n)^{2}+3

then find the value of

f(4)

\newline

Answer:

Given initial condition and formula: We are given the initial condition and the recursive formula for the function $f$ : $f(1) = 4$ $f(n+1) = f(n)^{2} + 3$ We need to find the value of $f(4)$ . We will start by finding $f(2)$ using the given recursive formula. Substitute $n=1$ into the recursive formula to find $f(2)$ . $f(2) = f(1)^{2} + 3$ $f(2) = 4^2 + 3$ $f(2) = 16 + 3$ $f(2) = 19$
Find $f(2)$ : Now that we have $f(2)$ , we will use it to find $f(3)$ . Substitute $n=2$ into the recursive formula to find $f(3)$ . $f(3) = f(2)^{2} + 3$ $f(3) = 19^{2} + 3$ $f(3) = 361 + 3$ $f(3) = 364$
Find $f(3)$ : Finally, we will use $f(3)$ to find $f(4)$ . Substitute $n=3$ into the recursive formula to find $f(4)$ . $f(4) = f(3)^{2} + 3$ $f(4) = 364^{2} + 3$ $f(4) = 132496 + 3$ $f(4) = 132499$