If f(1)=3 and f(n)=f(n-1)^(2)+5 then find the value of f(4). Answer:

Given f(1): We are given f(1) = 3. To find f(4), we need to find the values of f(2), f(3), and then f(4) using the recursive formula f(n) = f(n-1)^(2) + 5. First, let's find f(2). f(2) = f(1)^(2) + 5 = 3^2 + 5 = 9 + 5 = 14Find f(2): Now, let's find f(3) using the value of f(2). f(3) = f(2)^(2) + 5 = 14^2 + 5 = 196 + 5 = 201Find f(3): Finally, we find f(4) using the value of f(3). f(4) = f(3)^(2) + 5 = 201^2 + 5 = 40401 + 5 = 40406

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If
f(1)=3 and
f(n)=f(n-1)^(2)+5 then find the value of
f(4).
Answer:

If $f(1)=3$ and $f(n)=f(n-1)^{2}+5$ then find the value of $f(4)$ . $\newline$ Answer:

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Algebra 2

Evaluate expression when two complex numbers are given

Full solution

Q. If

f(1)=3

and

f(n)=f(n-1)^{2}+5

then find the value of

f(4)

\newline

Answer:

Given $f(1)$ : We are given $f(1) = 3$ . To find $f(4)$ , we need to find the values of $f(2)$ , $f(3)$ , and then $f(4)$ using the recursive formula $f(n) = f(n-1)^{2} + 5$ . First, let's find $f(2)$ . $f(2) = f(1)^{2} + 5 = 3^2 + 5 = 9 + 5 = 14$
Find $f(2)$ : Now, let's find $f(3)$ using the value of $f(2)$ . $f(3) = f(2)^{2} + 5 = 14^{2} + 5 = 196 + 5 = 201$
Find $f(3)$ : Finally, we find $f(4)$ using the value of $f(3)$ . $\newline$ $f(4) = f(3)^{2} + 5$ $\newline$ $= 201^{2} + 5$ $\newline$ $= 40401 + 5$ $\newline$ $= 40406$