If f(1)=3 and f(n)=f(n-1)^(2)-5 then find the value of f(3). Answer:

Find f(2): We are given the initial condition f(1) = 3 and the recursive formula f(n) = f(n-1)^(2) - 5. To find f(3), we first need to find f(2). Using the recursive formula, we substitute n = 2 to find f(2): f(2) = f(2-1)^(2) - 5 f(2) = f(1)^(2) - 5 f(2) = 3^(2) - 5 f(2) = 9 - 5 f(2) = 4Find f(3): Now that we have f(2), we can use it to find f(3). Using the recursive formula again, we substitute n = 3 to find f(3): f(3) = f(3-1)^(2) - 5 f(3) = f(2)^(2) - 5 f(3) = 4^(2) - 5 f(3) = 16 - 5 f(3) = 11

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If
f(1)=3 and
f(n)=f(n-1)^(2)-5 then find the value of
f(3).
Answer:

If $f(1)=3$ and $f(n)=f(n-1)^{2}-5$ then find the value of $f(3)$ . $\newline$ Answer:

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Math Problems

Algebra 2

Evaluate expression when two complex numbers are given

Full solution

Q. If

f(1)=3

and

f(n)=f(n-1)^{2}-5

then find the value of

f(3)

\newline

Answer:

Find $f(2)$ : We are given the initial condition $f(1) = 3$ and the recursive formula $f(n) = f(n-1)^{2} - 5$ . To find $f(3)$ , we first need to find $f(2)$ . Using the recursive formula, we substitute $n = 2$ to find $f(2)$ : $f(2) = f(2-1)^{2} - 5$ $f(2) = f(1)^{2} - 5$ $f(2) = 3^{2} - 5$ $f(1) = 3$ $0$ $f(1) = 3$ $1$
Find $f(3)$ : Now that we have $f(2)$ , we can use it to find $f(3)$ . Using the recursive formula again, we substitute $n = 3$ to find $f(3)$ : $f(3) = f(3-1)^{2} - 5$ $f(3) = f(2)^{2} - 5$ $f(3) = 4^{2} - 5$ $f(3) = 16 - 5$ $f(3) = 11$