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If 
f(1)=3 and 
f(n)=f(n-1)^(2)+2 then find the value of 
f(4).
Answer:

If f(1)=3 f(1)=3 and f(n)=f(n1)2+2 f(n)=f(n-1)^{2}+2 then find the value of f(4) f(4) .\newlineAnswer:

Full solution

Q. If f(1)=3 f(1)=3 and f(n)=f(n1)2+2 f(n)=f(n-1)^{2}+2 then find the value of f(4) f(4) .\newlineAnswer:
  1. Given initial condition: We are given the initial condition f(1)=3f(1) = 3 and the recursive formula f(n)=f(n1)2+2f(n) = f(n-1)^{2} + 2. To find f(4)f(4), we need to first find f(2)f(2), then f(3)f(3), and finally f(4)f(4) using the recursive formula.
  2. Find f(2)f(2): Using the recursive formula, let's find f(2)f(2):
    f(2)=f(1)2+2f(2) = f(1)^{2} + 2
    Substitute the value of f(1)f(1) into the equation:
    f(2)=32+2f(2) = 3^{2} + 2
    f(2)=9+2f(2) = 9 + 2
    f(2)=11f(2) = 11
  3. Find f(3)f(3): Now, let's find f(3)f(3) using the value of f(2)f(2):
    f(3)=f(2)2+2f(3) = f(2)^{2} + 2
    Substitute the value of f(2)f(2) into the equation:
    f(3)=112+2f(3) = 11^{2} + 2
    f(3)=121+2f(3) = 121 + 2
    f(3)=123f(3) = 123
  4. Find f(4)f(4): Finally, we can find f(4)f(4) using the value of f(3)f(3):
    f(4)=f(3)2+2f(4) = f(3)^{2} + 2
    Substitute the value of f(3)f(3) into the equation:
    f(4)=1232+2f(4) = 123^{2} + 2
    f(4)=15129+2f(4) = 15129 + 2
    f(4)=15131f(4) = 15131

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