If f(1)=2 and f(n)=f(n-1)^(2)-5 then find the value of f(4). Answer:

Given f(1): We are given f(1) = 2 and the recursive formula f(n) = f(n-1)^(2) - 5. To find f(4), we need to find the values of f(2), f(3), and then f(4) using the recursive formula.Find f(2): First, let's find f(2) using the given formula: f(2) = f(1)^(2) - 5 Substitute the value of f(1) into the formula: f(2) = (2)^(2) - 5 f(2) = 4 - 5 f(2) = -1Find f(3): Next, we find f(3) using the value of f(2): f(3) = f(2)^(2) - 5 Substitute the value of f(2) into the formula: f(3) = (-1)^(2) - 5 f(3) = 1 - 5 f(3) = -4Find f(4): Finally, we find f(4) using the value of f(3): f(4) = f(3)^(2) - 5 Substitute the value of f(3) into the formula: f(4) = (-4)^(2) - 5 f(4) = 16 - 5 f(4) = 11

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If
f(1)=2 and
f(n)=f(n-1)^(2)-5 then find the value of
f(4).
Answer:

If $f(1)=2$ and $f(n)=f(n-1)^{2}-5$ then find the value of $f(4)$ . $\newline$ Answer:

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Algebra 2

Evaluate expression when two complex numbers are given

Full solution

Q. If

f(1)=2

and

f(n)=f(n-1)^{2}-5

then find the value of

f(4)

\newline

Answer:

Given $f(1)$ : We are given $f(1) = 2$ and the recursive formula $f(n) = f(n-1)^{2} - 5$ . To find $f(4)$ , we need to find the values of $f(2)$ , $f(3)$ , and then $f(4)$ using the recursive formula.
Find $f(2)$ : First, let's find $f(2)$ using the given formula: $\newline$ $f(2) = f(1)^{2} - 5$ $\newline$ Substitute the value of $f(1)$ into the formula: $\newline$ $f(2) = (2)^{2} - 5$ $\newline$ $f(2) = 4 - 5$ $\newline$ $f(2) = -1$
Find $f(3)$ : Next, we find $f(3)$ using the value of $f(2)$ :
$f(3) = f(2)^{2} - 5$
Substitute the value of $f(2)$ into the formula:
$f(3) = (-1)^{2} - 5$
$f(3) = 1 - 5$
$f(3) = -4$
Find $f(4)$ : Finally, we find $f(4)$ using the value of $f(3)$ :
$f(4) = f(3)^{2} - 5$
Substitute the value of $f(3)$ into the formula:
$f(4) = (-4)^{2} - 5$
$f(4) = 16 - 5$
$f(4) = 11$