If f(1)=2 and f(n+1)=f(n)^(2)-5 then find the value of f(4). Answer:

Given f(1): We are given that f(1) = 2. To find f(4), we need to find the values of f(2), f(3), and then f(4) using the recursive formula f(n+1) = f(n)^(2) - 5.Find f(2): First, let's find f(2) using the given formula with n = 1. f(2) = f(1)^(2) - 5 = 2^2 - 5 = 4 - 5 = -1.Find f(3): Next, we find f(3) using the value of f(2). f(3) = f(2)^(2) - 5 = (-1)^2 - 5 = 1 - 5 = -4.Find f(4): Finally, we find f(4) using the value of f(3). f(4) = f(3)^(2) - 5 = (-4)^2 - 5 = 16 - 5 = 11.

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If
f(1)=2 and
f(n+1)=f(n)^(2)-5 then find the value of
f(4).
Answer:

If $f(1)=2$ and $f(n+1)=f(n)^{2}-5$ then find the value of $f(4)$ . $\newline$ Answer:

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Precalculus

Find the roots of factored polynomials

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Q. If

f(1)=2

and

f(n+1)=f(n)^{2}-5

then find the value of

f(4)

\newline

Answer:

Given $f(1)$ : We are given that $f(1) = 2$ . To find $f(4)$ , we need to find the values of $f(2)$ , $f(3)$ , and then $f(4)$ using the recursive formula $f(n+1) = f(n)^{2} - 5$ .
Find $f(2)$ : First, let's find $f(2)$ using the given formula with $n = 1$ .
$f(2) = f(1)^{2} - 5 = 2^{2} - 5 = 4 - 5 = -1$ .
Find $f(3)$ : Next, we find $f(3)$ using the value of $f(2)$ . $f(3) = f(2)^{2} - 5 = (-1)^2 - 5 = 1 - 5 = -4$ .
Find $f(4)$ : Finally, we find $f(4)$ using the value of $f(3)$ . $f(4) = f(3)^{2} - 5 = (-4)^{2} - 5 = 16 - 5 = 11$ .