If f(1)=2 and f(n+1)=f(n)^(2)-3 then find the value of f(3). Answer:

Given f(1): We are given that f(1) = 2. To find f(3), we need to find f(2) first, using the recursive formula f(n+1) = f(n)^(2) - 3.Find f(2): Using the recursive formula, we substitute n = 1 to find f(2): f(2) = f(1)^(2) - 3 = 2^2 - 3 = 4 - 3 = 1.Find f(3): Now that we have f(2), we can find f(3) by substituting n = 2 into the recursive formula: f(3) = f(2)^(2) - 3 = 1^2 - 3 = 1 - 3 = -2.

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If
f(1)=2 and
f(n+1)=f(n)^(2)-3 then find the value of
f(3).
Answer:

If $f(1)=2$ and $f(n+1)=f(n)^{2}-3$ then find the value of $f(3)$ . $\newline$ Answer:

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Precalculus

Find the roots of factored polynomials

Full solution

Q. If

f(1)=2

and

f(n+1)=f(n)^{2}-3

then find the value of

f(3)

\newline

Answer:

Given $f(1)$ : We are given that $f(1) = 2$ . To find $f(3)$ , we need to find $f(2)$ first, using the recursive formula $f(n+1) = f(n)^{2} - 3$ .
Find $f(2)$ : Using the recursive formula, we substitute $n = 1$ to find $f(2)$ : $f(2) = f(1)^{2} - 3 = 2^{2} - 3 = 4 - 3 = 1$ .
Find $f(3)$ : Now that we have $f(2)$ , we can find $f(3)$ by substituting $n = 2$ into the recursive formula: $f(3) = f(2)^{2} - 3 = 1^{2} - 3 = 1 - 3 = -2.$