If f(1)=2 and f(n+1)=f(n)^(2)-2 then find the value of f(3). Answer:

Given f(1) = 2: We are given that f(1) = 2. To find f(3), we need to find f(2) first, using the recursive formula f(n+1) = f(n)^(2) - 2. Let's calculate f(2) using f(1): f(2) = f(1)^(2) - 2 = 2^2 - 2 = 4 - 2 = 2.Calculate f(2): Now that we have f(2), we can use it to find f(3) using the same recursive formula: f(3) = f(2)^(2) - 2 = 2^2 - 2 = 4 - 2 = 2.

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If
f(1)=2 and
f(n+1)=f(n)^(2)-2 then find the value of
f(3).
Answer:

If $f(1)=2$ and $f(n+1)=f(n)^{2}-2$ then find the value of $f(3)$ . $\newline$ Answer:

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Precalculus

Find the roots of factored polynomials

Full solution

Q. If

f(1)=2

and

f(n+1)=f(n)^{2}-2

then find the value of

f(3)

\newline

Answer:

Given $f(1) = 2$ : We are given that $f(1) = 2$ . To find $f(3)$ , we need to find $f(2)$ first, using the recursive formula $f(n+1) = f(n)^{2} - 2$ . $\newline$ Let's calculate $f(2)$ using $f(1)$ : $\newline$ $f(2) = f(1)^{2} - 2 = 2^2 - 2 = 4 - 2 = 2$ .
Calculate $f(2)$ : Now that we have $f(2)$ , we can use it to find $f(3)$ using the same recursive formula: $f(3) = f(2)^{2} - 2 = 2^{2} - 2 = 4 - 2 = 2$ .