If f(1)=1,f(2)=3 and f(n)=f(n-1)+3f(n-2) then find the value of f(4). Answer:

Calculate f(3): To find f(4), we need to use the recursive formula f(n)=f(n-1)+3f(n-2). We already know f(1) and f(2), so we can find f(3) first. Calculation: f(3) = f(3-1) + 3f(3-2) = f(2) + 3f(1) = 3 + 3(1) = 3 + 3 = 6.Calculate f(4): Now that we have f(3), we can find f(4) using the same recursive formula. Calculation: f(4) = f(4-1) + 3f(4-2) = f(3) + 3f(2) = 6 + 3(3) = 6 + 9 = 15.

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If
f(1)=1,f(2)=3 and
f(n)=f(n-1)+3f(n-2) then find the value of
f(4).
Answer:

If $f(1)=1, f(2)=3$ and $f(n)=f(n-1)+3 f(n-2)$ then find the value of $f(4)$ . $\newline$ Answer:

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Precalculus

Find the roots of factored polynomials

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Q. If

f(1)=1, f(2)=3

and

f(n)=f(n-1)+3 f(n-2)

then find the value of

f(4)

\newline

Answer:

Calculate $f(3)$ : To find $f(4)$ , we need to use the recursive formula $f(n)=f(n-1)+3f(n-2)$ . We already know $f(1)$ and $f(2)$ , so we can find $f(3)$ first. $\newline$ Calculation: $f(3) = f(3-1) + 3f(3-2) = f(2) + 3f(1) = 3 + 3(1) = 3 + 3 = 6$ .
Calculate $f(4)$ : Now that we have $f(3)$ , we can find $f(4)$ using the same recursive formula. $\newline$ Calculation: $f(4) = f(4-1) + 3f(4-2) = f(3) + 3f(2) = 6 + 3(3) = 6 + 9 = 15$ .