If f(1)=1,f(2)=3 and f(n)=3f(n-1)-2f(n-2) then find the value of f(5). Answer:

Calculate f(3): To find f(5), we need to use the recursive formula f(n)=3f(n-1)-2f(n-2) to find the values of f(3), f(4), and then f(5). We already know f(1) and f(2), so we can start by finding f(3). Calculation: f(3) = 3f(2) - 2f(1) = 3*3 - 2*1 = 9 - 2 = 7.Calculate f(4): Now that we have f(3), we can find f(4) using the same recursive formula. Calculation: f(4) = 3f(3) - 2f(2) = 3*7 - 2*3 = 21 - 6 = 15.Calculate f(5): Finally, we can find f(5) using the values of f(4) and f(3). Calculation: f(5) = 3f(4) - 2f(3) = 3*15 - 2*7 = 45 - 14 = 31.

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If
f(1)=1,f(2)=3 and
f(n)=3f(n-1)-2f(n-2) then find the value of
f(5).
Answer:

If $f(1)=1, f(2)=3$ and $f(n)=3 f(n-1)-2 f(n-2)$ then find the value of $f(5)$ . $\newline$ Answer:

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Precalculus

Find the roots of factored polynomials

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Q. If

f(1)=1, f(2)=3

and

f(n)=3 f(n-1)-2 f(n-2)

then find the value of

f(5)

\newline

Answer:

Calculate $f(3)$ : To find $f(5)$ , we need to use the recursive formula $f(n)=3f(n-1)-2f(n-2)$ to find the values of $f(3)$ , $f(4)$ , and then $f(5)$ . We already know $f(1)$ and $f(2)$ , so we can start by finding $f(3)$ . $\newline$ Calculation: $f(3) = 3f(2) - 2f(1) = 3\times3 - 2\times1 = 9 - 2 = 7$ .
Calculate $f(4)$ : Now that we have $f(3)$ , we can find $f(4)$ using the same recursive formula. $\newline$ Calculation: $f(4) = 3f(3) - 2f(2) = 3\times7 - 2\times3 = 21 - 6 = 15$ .
Calculate $f(5)$ : Finally, we can find $f(5)$ using the values of $f(4)$ and $f(3)$ . $\newline$ Calculation: $f(5) = 3f(4) - 2f(3) = 3\times15 - 2\times7 = 45 - 14 = 31$ .