If f(1)=1 and f(n+1)=f(n)^(2)-2 then find the value of f(4). Answer:

Given f(1): We are given that f(1) = 1. To find f(4), we need to find the values of f(2), f(3), and then f(4) using the recursive formula f(n+1) = f(n)^(2) - 2.Find f(2): First, let's find f(2). We use the given formula with n=1: f(2) = f(1)^(2) - 2 = 1^2 - 2 = 1 - 2 = -1.Find f(3): Next, we find f(3) using the value of f(2): f(3) = f(2)^(2) - 2 = (-1)^2 - 2 = 1 - 2 = -1.Find f(4): Finally, we find f(4) using the value of f(3): f(4) = f(3)^(2) - 2 = (-1)^2 - 2 = 1 - 2 = -1.

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If
f(1)=1 and
f(n+1)=f(n)^(2)-2 then find the value of
f(4).
Answer:

If $f(1)=1$ and $f(n+1)=f(n)^{2}-2$ then find the value of $f(4)$ . $\newline$ Answer:

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Precalculus

Find the roots of factored polynomials

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Q. If

f(1)=1

and

f(n+1)=f(n)^{2}-2

then find the value of

f(4)

\newline

Answer:

Given $f(1)$ : We are given that $f(1) = 1$ . To find $f(4)$ , we need to find the values of $f(2)$ , $f(3)$ , and then $f(4)$ using the recursive formula $f(n+1) = f(n)^{2} - 2$ .
Find $f(2)$ : First, let's find $f(2)$ . We use the given formula with $n=1$ : $f(2) = f(1)^{2} - 2 = 1^2 - 2 = 1 - 2 = -1.$
Find $f(3)$ : Next, we find $f(3)$ using the value of $f(2)$ : $f(3) = f(2)^{2} - 2 = (-1)^{2} - 2 = 1 - 2 = -1$ .
Find $f(4)$ : Finally, we find $f(4)$ using the value of $f(3)$ : $f(4) = f(3)^{2} - 2 = (-1)^2 - 2 = 1 - 2 = -1$ .