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If 
f(1)=1 and 
f(n+1)=f(n)^(2)+2 then find the value of 
f(3).
Answer:

If f(1)=1 f(1)=1 and f(n+1)=f(n)2+2 f(n+1)=f(n)^{2}+2 then find the value of f(3) f(3) .\newlineAnswer:

Full solution

Q. If f(1)=1 f(1)=1 and f(n+1)=f(n)2+2 f(n+1)=f(n)^{2}+2 then find the value of f(3) f(3) .\newlineAnswer:
  1. Given f(1)=1f(1)=1: We are given that f(1)=1f(1)=1. To find f(3)f(3), we first need to find f(2)f(2) using the recursive formula f(n+1)=f(n)2+2f(n+1)=f(n)^{2}+2.\newlineCalculate f(2)f(2) using f(1)f(1):\newlinef(2)=f(1)2+2f(2) = f(1)^{2} + 2\newlinef(2)=12+2f(2) = 1^{2} + 2\newlinef(2)=1+2f(2) = 1 + 2\newlinef(1)=1f(1)=100
  2. Calculate f(2)f(2): Now that we have f(2)=3f(2)=3, we can use this value to find f(3)f(3) using the same recursive formula.\newlineCalculate f(3)f(3) using f(2)f(2):\newlinef(3)=f(2)2+2f(3) = f(2)^{2} + 2\newlinef(3)=32+2f(3) = 3^{2} + 2\newlinef(3)=9+2f(3) = 9 + 2\newlinef(3)=11f(3) = 11

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