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If a=2a=2 and b=2ib=2i, then find the value of the ab3ab^{3} in fully simplified form.

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Q. If a=2a=2 and b=2ib=2i, then find the value of the ab3ab^{3} in fully simplified form.
  1. Given: a,ba, b: Given: \newlinea=2a = 2\newlineb=2ib = 2i\newlineFind b3b^3.\newlineb=2ib = 2i\newlineb3=(2i)3b^3 = (2i)^3\newlineb3=2i×2i×2ib^3 = 2i \times 2i \times 2i\newlineb3=8ib^3 = -8i
  2. Find b3b^3: We have: \newlinea=2a = 2\newlineb3=8ib^3 = -8i\newlineNow calculate the expression for ab3ab^3.\newlineab3=2×(8i)ab^3 = 2 \times (-8i)\newlineab3=16iab^3 = -16i

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