If a_(1)=6 and a_(n)=na_(n-1)+5 then find the value of a_(4). Answer:

Find a_(2): To find the value of a_(4), we need to use the recursive formula a_(n)=na_(n-1)+5. We start by finding a_(2) using the given a_(1)=6. a_(2) = 2 * a_(1) + 5 = 2 * 6 + 5 = 12 + 5 = 17.Find a_(3): Next, we find a_(3) using the value of a_(2) we just found. a_(3) = 3 * a_(2) + 5 = 3 * 17 + 5 = 51 + 5 = 56.Find a_(4): Finally, we find a_(4) using the value of a_(3). a_(4) = 4 * a_(3) + 5 = 4 * 56 + 5 = 224 + 5 = 229.

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If
a_(1)=6 and
a_(n)=na_(n-1)+5 then find the value of
a_(4).
Answer:

If $a_{1}=6$ and $a_{n}=n a_{n-1}+5$ then find the value of $a_{4}$ . $\newline$ Answer:

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Precalculus

Find the roots of factored polynomials

Full solution

Q. If

a_{1}=6

and

a_{n}=n a_{n-1}+5

then find the value of

a_{4}

\newline

Answer:

Find $a_{2}$ : To find the value of $a_{4}$ , we need to use the recursive formula $a_{n}=na_{n-1}+5$ . We start by finding $a_{2}$ using the given $a_{1}=6$ . $\newline$ $a_{2} = 2 \times a_{1} + 5 = 2 \times 6 + 5 = 12 + 5 = 17$ .
Find $a_{3}$ : Next, we find $a_{3}$ using the value of $a_{2}$ we just found. $a_{3} = 3 \times a_{2} + 5 = 3 \times 17 + 5 = 51 + 5 = 56$ .
Find $a_{4}$ : Finally, we find $a_{4}$ using the value of $a_{3}$ . $a_{4} = 4 \times a_{3} + 5 = 4 \times 56 + 5 = 224 + 5 = 229$ .