If a_(1)=5,a_(2)=1 and a_(n)=a_(n-1)-a_(n-2) then find the value of a_(6). Answer:

Given Sequence and Formula: We are given the first two terms of the sequence: a_(1) = 5 and a_(2) = 1. The recursive formula for the sequence is a_(n) = a_(n-1) - a_(n-2). We need to find a_(6).Find a_(3): To find a_(6), we first need to find a_(3) using the recursive formula. We have a_(3) = a_(2) - a_(1) = 1 - 5 = -4.Find a_(4): Next, we find a_(4) using the recursive formula. We have a_(4) = a_(3) - a_(2) = -4 - 1 = -5.Find a_(5): Now, we find a_(5) using the recursive formula. We have a_(5) = a_(4) - a_(3) = -5 - (-4) = -1.Find a_(6): Finally, we find a_(6) using the recursive formula. We have a_(6) = a_(5) - a_(4) = -1 - (-5) = 4.

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If
a_(1)=5,a_(2)=1 and
a_(n)=a_(n-1)-a_(n-2) then find the value of
a_(6).
Answer:

If $a_{1}=5, a_{2}=1$ and $a_{n}=a_{n-1}-a_{n-2}$ then find the value of $a_{6}$ . $\newline$ Answer:

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Precalculus

Add, subtract, multiply, and divide complex numbers

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Q. If

a_{1}=5, a_{2}=1

and

a_{n}=a_{n-1}-a_{n-2}

then find the value of

a_{6}

\newline

Answer:

Given Sequence and Formula: We are given the first two terms of the sequence: $a_{1} = 5$ and $a_{2} = 1$ . The recursive formula for the sequence is $a_{n} = a_{n-1} - a_{n-2}$ . We need to find $a_{6}$ .
Find $a_{3}$ : To find $a_{6}$ , we first need to find $a_{3}$ using the recursive formula. We have $a_{3} = a_{2} - a_{1} = 1 - 5 = -4$ .
Find $a_{4}$ : Next, we find $a_{4}$ using the recursive formula. We have $a_{4} = a_{3} - a_{2} = -4 - 1 = -5$ .
Find $a_{5}$ : Now, we find $a_{5}$ using the recursive formula. We have $a_{5} = a_{4} - a_{3} = -5 - (-4) = -1$ .
Find $a_{6}$ : Finally, we find $a_{6}$ using the recursive formula. We have $a_{6} = a_{5} - a_{4} = -1 - (-5) = 4$ .