If a_(1)=4 and a_(n)=2a_(n-1)+4 then find the value of a_(3). Answer:

Given Sequence and Formula: We are given the first term of the sequence, a_(1)=4, and the recursive formula a_(n)=2a_(n-1)+4. To find a_(3), we first need to find a_(2) using the recursive formula.Find a_(2): Using the recursive formula a_(n)=2a_(n-1)+4, we substitute n=2 to find a_(2): a_(2) = 2a_(1) + 4 = 2*4 + 4 = 8 + 4 = 12.Find a_(3): Now that we have a_(2), we can use it to find a_(3) using the same recursive formula: a_(3) = 2a_(2) + 4 = 2*12 + 4 = 24 + 4 = 28.

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If
a_(1)=4 and
a_(n)=2a_(n-1)+4 then find the value of
a_(3).
Answer:

If $a_{1}=4$ and $a_{n}=2 a_{n-1}+4$ then find the value of $a_{3}$ . $\newline$ Answer:

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Precalculus

Find the roots of factored polynomials

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Q. If

a_{1}=4

and

a_{n}=2 a_{n-1}+4

then find the value of

a_{3}

\newline

Answer:

Given Sequence and Formula: We are given the first term of the sequence, $a_{1}=4$ , and the recursive formula $a_{n}=2a_{n-1}+4$ . To find $a_{3}$ , we first need to find $a_{2}$ using the recursive formula.
Find $a_{2}$ : Using the recursive formula $a_{n}=2a_{n-1}+4$ , we substitute $n=2$ to find $a_{2}$ : $a_{2} = 2a_{1} + 4 = 2\times4 + 4 = 8 + 4 = 12$ .
Find $a_{3}$ : Now that we have $a_{2}$ , we can use it to find $a_{3}$ using the same recursive formula: $\newline$ $a_{3} = 2a_{2} + 4 = 2\times12 + 4 = 24 + 4 = 28$ .