If a_(1)=2,a_(2)=0 and a_(n)=a_(n-1)-a_(n-2) then find the value of a_(4). Answer:

Calculate a_(3): To find the value of a_(4), we need to use the recursive formula a_(n)=a_(n-1)-a_(n-2). We already know a_(1) and a_(2), so we can calculate a_(3) first. a_(3) = a_(2) - a_(1) = 0 - 2 = -2.Calculate a_(4): Now that we have a_(3), we can use it along with a_(2) to find a_(4). a_(4) = a_(3) - a_(2) = -2 - 0 = -2.

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If
a_(1)=2,a_(2)=0 and
a_(n)=a_(n-1)-a_(n-2) then find the value of
a_(4).
Answer:

If $a_{1}=2, a_{2}=0$ and $a_{n}=a_{n-1}-a_{n-2}$ then find the value of $a_{4}$ . $\newline$ Answer:

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Math Problems

Precalculus

Find the roots of factored polynomials

Full solution

Q. If

a_{1}=2, a_{2}=0

and

a_{n}=a_{n-1}-a_{n-2}

then find the value of

a_{4}

\newline

Answer:

Calculate $a_{3}$ : To find the value of $a_{4}$ , we need to use the recursive formula $a_{n}=a_{n-1}-a_{n-2}$ . We already know $a_{1}$ and $a_{2}$ , so we can calculate $a_{3}$ first. $\newline$ $a_{3} = a_{2} - a_{1} = 0 - 2 = -2$ .
Calculate $a_{4}$ : Now that we have $a_{3}$ , we can use it along with $a_{2}$ to find $a_{4}$ . $\newline$ $a_{4} = a_{3} - a_{2} = -2 - 0 = -2$ .