If a_(1)=1,a_(2)=3 and a_(n)=a_(n-1)+a_(n-2) then find the value of a_(4). Answer:

Find a_(3): To find a_(4), we need to first find a_(3) using the recursive formula a_(n)=a_(n-1)+a_(n-2). We know that a_(1)=1 and a_(2)=3. So, a_(3)=a_(2)+a_(1)=3+1=4.Calculate a_(4): Now that we have a_(3), we can find a_(4) using the same recursive formula. a_(4)=a_(3)+a_(2)=4+3=7.Verify solution: We have successfully calculated a_(4) without any mathematical errors.

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If
a_(1)=1,a_(2)=3 and
a_(n)=a_(n-1)+a_(n-2) then find the value of
a_(4).
Answer:

If $a_{1}=1, a_{2}=3$ and $a_{n}=a_{n-1}+a_{n-2}$ then find the value of $a_{4}$ . $\newline$ Answer:

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Math Problems

Precalculus

Find the roots of factored polynomials

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Q. If

a_{1}=1, a_{2}=3

and

a_{n}=a_{n-1}+a_{n-2}

then find the value of

a_{4}

\newline

Answer:

Find $a_{3}$ : To find $a_{4}$ , we need to first find $a_{3}$ using the recursive formula $a_{n}=a_{n-1}+a_{n-2}$ . $\newline$ We know that $a_{1}=1$ and $a_{2}=3$ . $\newline$ So, $a_{3}=a_{2}+a_{1}=3+1=4$ .
Calculate $a_{4}$ : Now that we have $a_{3}$ , we can find $a_{4}$ using the same recursive formula. $a_{4}=a_{3}+a_{2}=4+3=7.$
Verify solution: We have successfully calculated $a_{4}$ without any mathematical errors.