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If 
-8x+4y=-6 is a true equation, what would be the value of 
-16x+8y?
Answer:

If 8x+4y=6 -8 x+4 y=-6 is a true equation, what would be the value of 16x+8y? -\mathbf{1 6 x}+\mathbf{8 y} ? \newlineAnswer:

Full solution

Q. If 8x+4y=6 -8 x+4 y=-6 is a true equation, what would be the value of 16x+8y? -\mathbf{1 6 x}+\mathbf{8 y} ? \newlineAnswer:
  1. Identify Relationship: Identify the relationship between the two equations.\newlineThe equation 16x+8y-16x+8y is exactly twice the given equation 8x+4y=6-8x+4y=-6.
  2. Multiply by 22: Multiply the entire given equation by 22 to find the value of 16x+8y-16x+8y.2×(8x+4y)=2×(6)2 \times (-8x+4y) = 2 \times (-6)
  3. Perform Multiplication: Perform the multiplication to get the new equation.\newline16x+8y=12-16x + 8y = -12
  4. Conclude Value: Conclude the value of 16x+8y-16x+8y. The value of 16x+8y-16x+8y is 12-12.

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