If -10x+y=4 and -2x-3y=-5 are true equations, what would be the value of -8x+4y ? Answer:

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If  -10x+y=4 and  -2x-3y=-5 are true equations, what would be the value of  -8x+4y ? Answer:

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Identify Equations: Identify the system of equations to solve for x and y. We have the following system of equations: 1) -10x + y = 4 2) -2x - 3y = -5Isolate y: Isolate y in the first equation to use it for substitution. From equation 1), we get: y = 10x + 4Substitute and Solve: Substitute the expression for y from equation 1) into equation 2). Plugging y = 10x + 4 into equation 2), we get: -2x - 3(10x + 4) = -5Combine Terms: Distribute and combine like terms in the substituted equation. -2x - 30x - 12 = -5 -32x - 12 = -5Isolate x: Add 12 to both sides of the equation to isolate the term with x. -32x - 12 + 12 = -5 + 12 -32x = 7Solve for x: Divide both sides by -32 to solve for x. x = 7 / -32 x = -7/32Substitute for y: Substitute the value of x back into the expression for y. y = 10(-7/32) + 4 y = -70/32 + 4Combine Fractions: Convert 4 to a fraction with a denominator of 32 to combine with -70/32. 4 = 128/32 y = -70/32 + 128/32Add Fractions: Add the fractions to find the value of y. y = (-70 + 128) / 32 y = 58/32 y = 29/16Calculate Expression: Now that we have the values of x and y, calculate -8x + 4y. -8x + 4y = -8(-7/32) + 4(29/16)Simplify Expression: Multiply the values to simplify the expression. -8x + 4y = 56/32 + 116/16Convert to Decimal: Simplify the fractions by reducing them to the same denominator or converting to whole numbers. 56/32 = 7/4 (since 56 and 32 are both divisible by 8) 116/16 = 7.25 (since 116 divided by 16 is 7.25) -8x + 4y = 7/4 + 7.25Add Values: Convert 7/4 to a decimal to add it to 7.25. 7/4 = 1.75 -8x + 4y = 1.75 + 7.25Add the decimal values to find the final answer. -8x + 4y = 1.75 + 7.25 -8x + 4y = 9

If $-\mathbf{1 0 x}+\mathbf{y}=\mathbf{4}$ and $-\mathbf{2 x}-\mathbf{3 y}=-\mathbf{5}$ are true equations, what would be the value of $-8 x+4 y$ ? $\newline$ Answer:

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If −10x+y=4 -\mathbf{1 0 x}+\mathbf{y}=\mathbf{4} −10x+y=4 and −2x−3y=−5 -\mathbf{2 x}-\mathbf{3 y}=-\mathbf{5} −2x−3y=−5 are true equations, what would be the value of −8x+4y -8 x+4 y −8x+4y ?\newlineAnswer:

If $-\mathbf{1 0 x}+\mathbf{y}=\mathbf{4}$ and $-\mathbf{2 x}-\mathbf{3 y}=-\mathbf{5}$ are true equations, what would be the value of $-8 x+4 y$ ? $\newline$ Answer: