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Let’s check out your problem:

How many solutions does the system have?

{[y=-2x-4],[y=3x+3]:}
Choose 1 answer:
(A) Exactly one solution
(B) No solutions
(C) Infinitely many solutions

How many solutions does the system have?\newline{y=2x4 y=3x+3\begin{cases} y=-2x-4\ \newline y=3x+3 \end{cases}\newlineChoose 11 answer:\newline(A) Exactly one solution\newline(B) No solutions\newline(C) Infinitely many solutions

Full solution

Q. How many solutions does the system have?\newline{y=2x4 y=3x+3\begin{cases} y=-2x-4\ \newline y=3x+3 \end{cases}\newlineChoose 11 answer:\newline(A) Exactly one solution\newline(B) No solutions\newline(C) Infinitely many solutions
  1. Given Equations: We are given a system of two linear equations:\newline11) y=2x4y = -2x - 4\newline22) y=3x+3y = 3x + 3\newlineTo find the number of solutions, we need to determine if the lines represented by these equations intersect, are parallel, or are the same line.
  2. Slope Comparison: First, let's compare the slopes of the two lines. The slope of the first equation is 2-2, and the slope of the second equation is 33. Since the slopes are not equal, the lines are not parallel.
  3. Intersection Point: Because the lines are not parallel, they must intersect at exactly one point. Therefore, the system of equations has exactly one solution.