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How many solutions does the system have?

{[20 x-5y=5],[4x-y=1]:}
Choose 1 answer:
(A) Exactly one solution
(B) No solutions
(C) Infinitely many solutions

How many solutions does the system have?\newline{20x5y=54xy=1 \left\{\begin{array}{l} 20 x-5 y=5 \\ 4 x-y=1 \end{array}\right. \newlineChoose 11 answer:\newline(A) Exactly one solution\newline(B) No solutions\newline(C) Infinitely many solutions

Full solution

Q. How many solutions does the system have?\newline{20x5y=54xy=1 \left\{\begin{array}{l} 20 x-5 y=5 \\ 4 x-y=1 \end{array}\right. \newlineChoose 11 answer:\newline(A) Exactly one solution\newline(B) No solutions\newline(C) Infinitely many solutions
  1. Write System of Equations: Write down the system of equations to analyze.\newlineThe system is:\newline{20x5y=54xy=1 \begin{cases} 20x - 5y = 5 \\ 4x - y = 1 \end{cases} \newlineWe want to determine if this system has exactly one solution, no solutions, or infinitely many solutions.
  2. Simplify the System: Look for a way to simplify the system.\newlineNotice that the first equation can be simplified by dividing every term by 55, which would give us the second equation. Let's do that:\newline20x55y5=55 \frac{20x}{5} - \frac{5y}{5} = \frac{5}{5} \newline4xy=1 4x - y = 1 \newlineThis is the same as the second equation in the system.
  3. Determine Relationship: Determine the relationship between the two equations.\newlineSince the simplified form of the first equation is identical to the second equation, we have two identical equations. This means that every solution to one equation is also a solution to the other.
  4. Conclude Number of Solutions: Conclude the number of solutions.\newlineBecause the two equations are identical, the system does not have a unique solution. Instead, it has infinitely many solutions, as every point on the line represented by the equation 4xy=1 4x - y = 1 is a solution to the system.