How does h(x)=7x - 3 change over the interval from x=-1 to x=2 ?\n\nh(x) increases by a factor of 3\n\nh(x) decreases by 21\n\nh(x) increases by 30\n\nh(x) decreases by 21

Find h(-1): Find h(-1). h(x) = 7x - 3 h(-1) = 7(-1) - 3 h(-1) = -7 - 3 h(-1) = -10Find h(2): Find h(2). h(x) = 7x - 3 h(2) = 7(2) - 3 h(2) = 14 - 3 h(2) = 11Calculate change: Calculate the change from h(-1) to h(2). h(-1) = -10 h(2) = 11 Change = h(2) - h(-1) Change = 11 - (-10) Change = 11 + 10 Change = 21Determine increase or decrease: Determine if h(x) increases or decreases. Since h(2) > h(-1), h(x) increases.Check given choices: Check the given choices. h(x) increases by 21.

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How does $h(x)=7x - 3$ change over the interval from $x=-1$ to $x=2$ ? $\newline$ $h(x)$ increases by a factor of $3$ $\newline$ $h(x)$ decreases by $21$ $\newline$ $h(x)$ increases by $30$ $\newline$ $h(x)$ decreases by $21$

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Algebra 2

Exponential functions over unit intervals

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Q. How does

h(x)=7x - 3

change over the interval from

x=-1

x=2

\newline

h(x)

increases by a factor of

3

\newline

h(x)

decreases by

21

\newline

h(x)

increases by

30

\newline

h(x)

decreases by

21

Find $h(-1)$ : Find $h(-1)$ .
$h(x) = 7x - 3$
$h(-1) = 7(-1) - 3$
$h(-1) = -7 - 3$
$h(-1) = -10$
Find $h(2)$ : Find $h(2)$ . $h(x) = 7x - 3$ $h(2) = 7(2) - 3$ $h(2) = 14 - 3$ $h(2) = 11$
Calculate change: Calculate the change from $h(-1)$ to $h(2)$ . $h(-1) = -10$ $h(2) = 11$ Change = $h(2) - h(-1)$ Change = $11 - (-10)$ Change = $11 + 10$ Change = $21$
Determine increase or decrease: Determine if $h(x)$ increases or decreases. Since h(2) > h(-1), $h(x)$ increases.
Check given choices: Check the given choices. $h(x)$ increases by $21$ .