How does h(t)=-5t-2 change over the interval from t=-1 to t=2 ?\n\nh(t) decreases by a factor of 3\n\nh(t) decreases by 15\n\nh(t) increases by 18\n\nh(t) increases by 15

Given function: We have: h(t) = -5t - 2 Find the value of h(-1). Substitute t = -1 in h(t) = -5t - 2. h(-1) = -5(-1) - 2 h(-1) = 5 - 2 h(-1) = 3Find h(-1): We have: h(t) = -5t - 2 Find the value of h(2). Substitute t = 2 in h(t) = -5t - 2. h(2) = -5(2) - 2 h(2) = -10 - 2 h(2) = -12Find h(2): We found: h(-1) = 3 h(2) = -12 Is h(t) increasing or decreasing over t = -1 to t = 2? We know that h(-1) = 3 and h(2) = -12. h(t) decreases from 3 to -12.Increasing or decreasing: We have: h(-1) = 3 h(2) = -12 Calculate the change from t = -1 to t = 2. Change = h(2) - h(-1) Change = -12 - 3 Change = -15Calculate change: How does h(t) = -5t - 2 change over the interval from t = -1 to t = 2? h(t) decreases by 15 over the interval from t = -1 to t = 2.

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How does $h(t)=-5t-2$ change over the interval from $t=-1$ to $t=2$ ? $\newline$ $h(t)$ decreases by a factor of $3$ $\newline$ $h(t)$ decreases by $15$ $\newline$ $h(t)$ increases by $18$ $\newline$ $h(t)$ increases by $15$

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Algebra 2

Exponential functions over unit intervals

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Q. How does

h(t)=-5t-2

change over the interval from

t=-1

t=2

\newline

h(t)

decreases by a factor of

3

\newline

h(t)

decreases by

15

\newline

h(t)

increases by

18

\newline

h(t)

increases by

15

Given function: We have: $h(t) = -5t - 2$ Find the value of $h(-1)$ . Substitute $t = -1$ in $h(t) = -5t - 2$ . $h(-1) = -5(-1) - 2$ $h(-1) = 5 - 2$ $h(-1) = 3$
Find $h(-1)$ : We have: $h(t) = -5t - 2$ Find the value of $h(2)$ . Substitute $t = 2$ in $h(t) = -5t - 2$ . $h(2) = -5(2) - 2$ $h(2) = -10 - 2$ $h(2) = -12$
Find $h(2)$ : We found: $h(-1) = 3$ $h(2) = -12$ Is $h(t)$ increasing or decreasing over $t = -1$ to $t = 2$ ? We know that $h(-1) = 3$ and $h(2) = -12$ . $h(t)$ decreases from $3$ to $h(-1) = 3$ $0$ .
Increasing or decreasing: We have: $h(-1) = 3$ $h(2) = -12$ Calculate the change from $t = -1$ to $t = 2$ . Change = $h(2) - h(-1)$ Change = $-12 - 3$ Change = $-15$
Calculate change: How does $h(t) = -5t - 2$ change over the interval from $t = -1$ to $t = 2$ ? $h(t)$ decreases by $15$ over the interval from $t = -1$ to $t = 2$ .