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h=x(V-5x)
The equation shown gives the height, 
h, in meters, of a spray of water from a particular lawn sprinkler at a distance, 
x meters from the sprinkler when the water is traveling at a velocity, 
V, in meters per second. The maximum spraying distance is the horizontal distance from the sprinkler where the water reaches the ground. If the velocity is quadrupled, how does the maximum spraying distance change?
Choose 1 answer:
(A) The maximum spraying distance is halved.
(B) The maximum spraying distance is doubled.
(C) The maximum spraying distance is quadrupled.
(D) The maximum spraying distance is multiplied by 16.

h=x(V5x) h=x(V-5 x) \newlineThe equation shown gives the height, h h , in meters, of a spray of water from a particular lawn sprinkler at a distance, x x meters from the sprinkler when the water is traveling at a velocity, V V , in meters per second. The maximum spraying distance is the horizontal distance from the sprinkler where the water reaches the ground. If the velocity is quadrupled, how does the maximum spraying distance change?\newlineChoose 11 answer:\newline(A) The maximum spraying distance is halved.\newline(B) The maximum spraying distance is doubled.\newline(C) The maximum spraying distance is quadrupled.\newline(D) The maximum spraying distance is multiplied by 1616.

Full solution

Q. h=x(V5x) h=x(V-5 x) \newlineThe equation shown gives the height, h h , in meters, of a spray of water from a particular lawn sprinkler at a distance, x x meters from the sprinkler when the water is traveling at a velocity, V V , in meters per second. The maximum spraying distance is the horizontal distance from the sprinkler where the water reaches the ground. If the velocity is quadrupled, how does the maximum spraying distance change?\newlineChoose 11 answer:\newline(A) The maximum spraying distance is halved.\newline(B) The maximum spraying distance is doubled.\newline(C) The maximum spraying distance is quadrupled.\newline(D) The maximum spraying distance is multiplied by 1616.
  1. Analyze Equation h=x(V5x)h = x(V - 5x): Let's analyze the given equation h=x(V5x)h = x(V - 5x) to understand how the height of the spray depends on the distance xx from the sprinkler and the velocity VV. The maximum spraying distance occurs when the height hh becomes zero, because that's when the water reaches the ground.
  2. Set hh to zero: Setting hh to zero for the maximum spraying distance, we get 0=x(V5x)0 = x(V - 5x). This simplifies to V5x=0V - 5x = 0, because if xx were zero, we wouldn't be talking about a distance from the sprinkler. So, we solve for xx to find the maximum spraying distance.
  3. Solve for x: Solving V5x=0V - 5x = 0 for xx gives us x=V5x = \frac{V}{5}. This is the original maximum spraying distance with the initial velocity VV.
  4. Substitute new velocity: Now, if the velocity is quadrupled, the new velocity is 4V4V. We substitute this into the equation for xx to find the new maximum spraying distance: x=4V5x = \frac{4V}{5}.
  5. Correct substitution: However, we made a mistake in the previous step. The correct substitution should be into the original equation V5x=0V - 5x = 0, replacing VV with 4V4V. So the new equation is 4V5x=04V - 5x = 0.

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