Given the function f(x)=(5)/(2)x^(3)+(1)/(6)x^(2), then what is -2f(x) as a simplified polynomial? Answer:

Multiply by -2: We are given the function f(x) = (5/2)x^3 + (1/6)x^2. To find -2f(x), we need to multiply the entire function by -2. -2f(x) = -2 * ((5/2)x^3 + (1/6)x^2)Distribute -2: Now, distribute the -2 to both terms in the function. -2f(x) = -2 * (5/2)x^3 + -2 * (1/6)x^2Simplify terms: Simplify each term by multiplying the coefficients. -2f(x) = -5x^3 + (-1/3)x^2Final result: The polynomial is now simplified, and there is no need for further simplification. So, -2f(x) = -5x^3 - (1/3)x^2

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Given the function
f(x)=(5)/(2)x^(3)+(1)/(6)x^(2), then what is
-2f(x) as a simplified polynomial?
Answer:

Given the function $f(x)=\frac{5}{2} x^{3}+\frac{1}{6} x^{2}$ , then what is $-2 f(x)$ as a simplified polynomial? $\newline$ Answer:

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Algebra 2

Composition of linear and quadratic functions: find an equation

Full solution

Q. Given the function

f(x)=\frac{5}{2} x^{3}+\frac{1}{6} x^{2}

, then what is

-2 f(x)

as a simplified polynomial?

\newline

Answer:

Multiply by $-2$ : We are given the function $f(x) = \frac{5}{2}x^3 + \frac{1}{6}x^2$ . To find $-2f(x)$ , we need to multiply the entire function by $-2$ . $\newline$ $-2f(x) = -2 \times (\frac{5}{2}x^3 + \frac{1}{6}x^2)$
Distribute $-2$ : Now, distribute the $-2$ to both terms in the function. $\newline$ $-2f(x) = -2 \times \left(\frac{5}{2}\right)x^3 + -2 \times \left(\frac{1}{6}\right)x^2$
Simplify terms: Simplify each term by multiplying the coefficients. $\newline$ $-2f(x) = -5x^3 + \left(-\frac{1}{3}\right)x^2$
Final result: The polynomial is now simplified, and there is no need for further simplification. $\newline$ So, $-2f(x) = -5x^3 - \left(\frac{1}{3}\right)x^2$