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Given the following system of equations, find the value of 
y :

{:[4y+14 x=10],[-2y-4x=4]:}

Given the following system of equations, find the value of y y :\newline4y+14x=102y4x=4 \begin{array}{l} 4 y+14 x=10 \\ -2 y-4 x=4 \end{array}

Full solution

Q. Given the following system of equations, find the value of y y :\newline4y+14x=102y4x=4 \begin{array}{l} 4 y+14 x=10 \\ -2 y-4 x=4 \end{array}
  1. Write Equations: Write down the system of equations.\newlineWe have the following system of equations:\newline4y+14x=104y + 14x = 10\newline2y4x=4-2y - 4x = 4
  2. Multiply Second Equation: Multiply the second equation by 22 to make the coefficient of yy in both equations the same (but opposite in sign).\newlineMultiplying the second equation by 22 gives us:\newline4y8x=8-4y - 8x = 8
  3. Add Equations: Add the modified second equation to the first equation to eliminate yy.
    (4y+14x)+(4y8x)=10+8(4y + 14x) + (-4y - 8x) = 10 + 8
    This simplifies to:
    4y4y+14x8x=10+84y - 4y + 14x - 8x = 10 + 8
    0y+6x=180y + 6x = 18
    Since the yy terms cancel out, we are left with an equation in xx only.
  4. Correct Mistake: Realize that we made a mistake in the previous step. We should have added the equations directly without modifying the second equation. Let's correct this.\newlineAdding the original second equation to the first equation gives us:\newline(4y+14x)+(2y4x)=10+4(4y + 14x) + (-2y - 4x) = 10 + 4\newlineThis simplifies to:\newline4y2y+14x4x=10+44y - 2y + 14x - 4x = 10 + 4\newline2y+10x=142y + 10x = 14