Q. Given the following system of equations, find the value of y :4y+14x=10−2y−4x=4
Write Equations: Write down the system of equations.We have the following system of equations:4y+14x=10−2y−4x=4
Multiply Second Equation: Multiply the second equation by 2 to make the coefficient of y in both equations the same (but opposite in sign).Multiplying the second equation by 2 gives us:−4y−8x=8
Add Equations: Add the modified second equation to the first equation to eliminate y. (4y+14x)+(−4y−8x)=10+8 This simplifies to: 4y−4y+14x−8x=10+8 0y+6x=18 Since the y terms cancel out, we are left with an equation in x only.
Correct Mistake: Realize that we made a mistake in the previous step. We should have added the equations directly without modifying the second equation. Let's correct this.Adding the original second equation to the first equation gives us:(4y+14x)+(−2y−4x)=10+4This simplifies to:4y−2y+14x−4x=10+42y+10x=14