Q. Given that x=4v5+3, find dvd(3v4−5sinx) in terms of only v.Answer:
Find Derivative of 3v4: First, we need to find the derivative of the function 3v4 with respect to v. The derivative of vn with respect to v is n∗v(n−1). So, the derivative of 3v4 with respect to v is 4∗3v(4−1)=12v3.
Chain Rule for −5sin(x): Next, we need to find the derivative of −5sin(x) with respect to v. Since x is a function of v, we will use the chain rule. The chain rule states that the derivative of f(g(v)) with respect to v is f′(g(v))⋅g′(v). Here, f(x)=−5sin(x) and g(v)=4v5+3.
Derivative of −5sin(x): We first find the derivative of f(x)=−5sin(x) with respect to x, which is −5cos(x).
Derivative of 4v5+3: Now we find the derivative of g(v)=4v5+3 with respect to v, which is 20v4.
Apply Chain Rule: Applying the chain rule, we multiply the derivative of f with respect to x by the derivative of g with respect to v. This gives us the derivative of −5sin(x) with respect to v as −5cos(x)×20v4.
Express cos(x) in terms of v: Now we need to express cos(x) in terms of v, since x=4v5+3. However, there is no straightforward algebraic way to express cos(4v5+3) in terms of v, so we leave it as cos(4v5+3).
Combine Derivatives: Combining the derivatives of 3v4 and −5sin(x) with respect to v, we get the total derivative as 12v3−5cos(4v5+3)⋅20v4.
Simplify Final Answer: Simplify the expression to get the final answer.12v3−100v4cos(4v5+3) is the derivative of 3v4−5sin(x) with respect to v in terms of v.
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