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Given that 
x=3v^(3)+2, find 
(d)/(dv)(4v^(2)+5cos x) in terms of only 
v.
Answer:

Given that x=3v3+2 x=3 v^{3}+2 , find ddv(4v2+5cosx) \frac{d}{d v}\left(4 v^{2}+5 \cos x\right) in terms of only v v .\newlineAnswer:

Full solution

Q. Given that x=3v3+2 x=3 v^{3}+2 , find ddv(4v2+5cosx) \frac{d}{d v}\left(4 v^{2}+5 \cos x\right) in terms of only v v .\newlineAnswer:
  1. Find Derivative: First, we need to find the derivative of the function 4v2+5cos(x)4v^2 + 5\cos(x) with respect to vv. To do this, we will use the chain rule, which states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. The outer function in this case is 4v2+5cos(u)4v^2 + 5\cos(u), where uu is a function of vv, and the inner function is u(x)=x=3v3+2u(x) = x = 3v^3 + 2.
  2. Apply Chain Rule: We start by differentiating the outer function with respect to vv, treating xx as a constant for now. The derivative of 4v24v^2 with respect to vv is 8v8v. Since xx is treated as a constant, the derivative of 5cos(x)5\cos(x) with respect to vv is 00. So the derivative of the outer function with respect to vv is 8v8v.
  3. Differentiate Inner Function: Next, we need to differentiate the inner function x=3v3+2x = 3v^3 + 2 with respect to vv. The derivative of 3v33v^3 with respect to vv is 9v29v^2, and the derivative of the constant 22 with respect to vv is 00. So the derivative of the inner function with respect to vv is 9v29v^2.
  4. Apply Chain Rule Again: Now we apply the chain rule. We multiply the derivative of the outer function by the derivative of the inner function. The derivative of the outer function is 8v8v, and the derivative of the inner function is 9v29v^2. Therefore, the derivative of 4v24v^2 with respect to vv is 8v×9v2=72v38v \times 9v^2 = 72v^3.
  5. Combine Derivatives: However, we also need to differentiate the term 5cos(x)5\cos(x) with respect to vv using the chain rule. The derivative of cos(x)\cos(x) with respect to xx is sin(x)-\sin(x), and we already found that the derivative of xx with respect to vv is 9v29v^2. So the derivative of 5cos(x)5\cos(x) with respect to vv is vv00.
  6. Express in Terms of vv: Now we combine the derivatives of both terms to get the full derivative of the function with respect to vv. The derivative of 4v24v^2 is 72v372v^3, and the derivative of 5cos(x)5\cos(x) is 5sin(x)×9v2-5\sin(x) \times 9v^2. So the full derivative is 72v345v2sin(x)72v^3 - 45v^2\sin(x).
  7. Final Derivative: Finally, we need to express the derivative in terms of vv only. Since x=3v3+2x = 3v^3 + 2, we substitute this into the sine function to get sin(3v3+2)\sin(3v^3 + 2). The final derivative of the function with respect to vv is 72v345v2sin(3v3+2)72v^3 - 45v^2\sin(3v^3 + 2).

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