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Let’s check out your problem:
Given that
f
(
x
)
=
x
−
1
,
g
(
x
)
=
−
2
x
f(x)=x-1, \quad g(x)=-2 x
f
(
x
)
=
x
−
1
,
g
(
x
)
=
−
2
x
and
h
(
x
)
=
−
3
f
(
x
)
+
g
(
x
−
3
)
h(x)=-3 f(x)+g(x-3)
h
(
x
)
=
−
3
f
(
x
)
+
g
(
x
−
3
)
, then what is the value of
h
(
5
)
h(5)
h
(
5
)
?
\newline
Answer:
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Math Problems
Precalculus
Find the roots of factored polynomials
Full solution
Q.
Given that
f
(
x
)
=
x
−
1
,
g
(
x
)
=
−
2
x
f(x)=x-1, \quad g(x)=-2 x
f
(
x
)
=
x
−
1
,
g
(
x
)
=
−
2
x
and
h
(
x
)
=
−
3
f
(
x
)
+
g
(
x
−
3
)
h(x)=-3 f(x)+g(x-3)
h
(
x
)
=
−
3
f
(
x
)
+
g
(
x
−
3
)
, then what is the value of
h
(
5
)
h(5)
h
(
5
)
?
\newline
Answer:
Find
f
(
5
)
f(5)
f
(
5
)
:
First, we need to find the value of
f
(
5
)
f(5)
f
(
5
)
since
h
(
x
)
h(x)
h
(
x
)
involves
f
(
x
)
f(x)
f
(
x
)
.
f
(
x
)
=
x
−
1
f(x) = x - 1
f
(
x
)
=
x
−
1
f
(
5
)
=
5
−
1
=
4
f(5) = 5 - 1 = 4
f
(
5
)
=
5
−
1
=
4
Find
g
(
2
)
g(2)
g
(
2
)
:
Next, we need to find the value of
g
(
x
−
3
)
g(x-3)
g
(
x
−
3
)
. Since we are evaluating
h
(
5
)
h(5)
h
(
5
)
, we need to find
g
(
5
−
3
)
g(5-3)
g
(
5
−
3
)
.
\newline
g
(
x
)
=
−
2
x
g(x) = -2x
g
(
x
)
=
−
2
x
\newline
g
(
5
−
3
)
=
g
(
2
)
=
−
2
×
2
=
−
4
g(5-3) = g(2) = -2 \times 2 = -4
g
(
5
−
3
)
=
g
(
2
)
=
−
2
×
2
=
−
4
Calculate
h
(
5
)
h(5)
h
(
5
)
:
Now, we can use the values of
f
(
5
)
f(5)
f
(
5
)
and
g
(
2
)
g(2)
g
(
2
)
to find
h
(
5
)
h(5)
h
(
5
)
.
h
(
x
)
=
−
3
f
(
x
)
+
g
(
x
−
3
)
h(x) = -3f(x) + g(x-3)
h
(
x
)
=
−
3
f
(
x
)
+
g
(
x
−
3
)
h
(
5
)
=
−
3
f
(
5
)
+
g
(
2
)
h(5) = -3f(5) + g(2)
h
(
5
)
=
−
3
f
(
5
)
+
g
(
2
)
h
(
5
)
=
−
3
×
4
+
(
−
4
)
h(5) = -3 \times 4 + (-4)
h
(
5
)
=
−
3
×
4
+
(
−
4
)
h
(
5
)
=
−
12
−
4
h(5) = -12 - 4
h
(
5
)
=
−
12
−
4
h
(
5
)
=
−
16
h(5) = -16
h
(
5
)
=
−
16
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\newline
(
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+
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)
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x
+
4
)
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(
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(
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\newline
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\newline
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