Q. Given that f(x)=−4x,g(x)=x−4 and h(x)=−f(x−1)+3g(x), then what is the value of h(2) ?Answer:
Find f(x) at x=2: First, we need to find the value of f(x) when x=2. f(x)=−4x f(2)=−4×2 =−8
Calculate g(x) at x=2: Next, we calculate the value of g(x) when x=2. g(x)=x−4 g(2)=2−4 =−2
Find f(x−1) at x=2: Now, we need to find the value of f(x−1) when x=2. f(x−1)=−4(x−1) f(2−1)=−4(2−1) =−4(1) =−4
Calculate 3g(x) at x=2: We also need to calculate 3g(x) when x=2. 3g(x)=3(x−4) 3g(2)=3(2−4) =3(−2) =−6
Find h(x) using f(x−1) and 3g(x) at x=2: Now we can find h(x) using the values of −f(x−1) and 3g(x) when x=2. h(x)=−f(x−1)+3g(x) h(2)=−(−4)+(−6) f(x−1)0 f(x−1)1
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