Q. Given that f(x)=−3x,g(x)=x+1 and h(x)=2f(x−3)−2g(x), then what is the value of h(3) ?Answer:
Find f(0): First, we need to find the value of f(x) when x is replaced by (3−3), which is f(0).f(x)=−3xf(0)=−3(0)=0
Calculate g(3): Next, we calculate the value of g(x) when x is replaced by 3. g(x)=x+1 g(3)=3+1=4
Substitute values into h(x): Now, we can substitute the values of f(0) and g(3) into the equation for h(x). h(x)=2f(x−3)−2g(x) h(3)=2f(3−3)−2g(3)=2f(0)−2g(3) h(3)=2(0)−2(4)=0−8=−8