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Given that events A and B are independent with 
P(A)=0.95 and 
P(B)=0.4, determine the value of 
P(A∣B), rounding to the nearest thousandth, if necessary.
Answer:

Given that events A and B are independent with P(A)=0.95 P(A)=0.95 and P(B)=0.4 P(B)=0.4 , determine the value of P(AB) P(A \mid B) , rounding to the nearest thousandth, if necessary.\newlineAnswer:

Full solution

Q. Given that events A and B are independent with P(A)=0.95 P(A)=0.95 and P(B)=0.4 P(B)=0.4 , determine the value of P(AB) P(A \mid B) , rounding to the nearest thousandth, if necessary.\newlineAnswer:
  1. Probability of Independent Events: For independent events AA and BB, the probability of AA given BB, denoted as P(AB)P(A\mid B), is the same as the probability of AA, because the occurrence of BB does not affect the probability of AA. Therefore, P(AB)=P(A)P(A\mid B) = P(A).
  2. Calculation of P(A): We are given P(A)=0.95P(A) = 0.95. Since AA and BB are independent, P(AB)=P(A)P(A\mid B) = P(A).
  3. Final Value of P(AB)P(A|B): Now we can directly write the value of P(AB)P(A∣B) as 0.950.95.

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