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Given that events A and B are independent with 
P(A)=0.6 and 
P(B)=0.72, determine the value of 
P(A nn B), rounding to the nearest thousandth, if necessary.
Answer:

Given that events A and B are independent with P(A)=0.6 P(A)=0.6 and P(B)=0.72 P(B)=0.72 , determine the value of P(AB) P(A \cap B) , rounding to the nearest thousandth, if necessary.\newlineAnswer:

Full solution

Q. Given that events A and B are independent with P(A)=0.6 P(A)=0.6 and P(B)=0.72 P(B)=0.72 , determine the value of P(AB) P(A \cap B) , rounding to the nearest thousandth, if necessary.\newlineAnswer:
  1. Use Multiplication Rule: To find the probability of both independent events AA and BB occurring together, we use the multiplication rule for independent events. The rule states that P(AB)=P(A)×P(B)P(A \cap B) = P(A) \times P(B).
  2. Calculate P(AB)P(A \cap B): Now we calculate P(AB)P(A \cap B) using the given probabilities P(A)=0.6P(A) = 0.6 and P(B)=0.72P(B) = 0.72.\newlineP(AB)=0.6×0.72P(A \cap B) = 0.6 \times 0.72
  3. Perform Multiplication: Performing the multiplication, we get: P(AB)=0.432P(A \cap B) = 0.432
  4. Check Result: Since the problem asks for the answer rounded to the nearest thousandth if necessary, we check our result. The value 0.4320.432 is already rounded to the nearest thousandth, so no further action is needed.

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