Given that events A and B are independent with P(A)=0.1 and P(A and B)=0.041, determine the value of P(B), rounding to the nearest thousandth, if necessary.Answer:
Q. Given that events A and B are independent with P(A)=0.1 and P(A and B)=0.041, determine the value of P(B), rounding to the nearest thousandth, if necessary.Answer:
Calculate Product: Since events A and B are independent, the probability of A and B occurring together, P(A and B), is the product of their individual probabilities, P(A)×P(B).We are given:P(A)=0.1P(A and B)=0.041We can express P(A and B) as P(A)×P(B).So, we have the equation:B0
Find P(B): To find P(B), we need to divide both sides of the equation by P(A). P(B)=P(A)P(A and B) P(B)=0.10.041
Perform Division: Now we perform the division to find P(B). P(B)=0.10.041P(B)=0.41
Correct Division: Correcting the division from the previous step:P(B) = 0.041/0.1P(B) = 0.41 (This was incorrect.)The correct division is:P(B) = 0.041/0.1P(B) = 0.41 (This is still incorrect.)