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Given that events A and B are independent with 
P(A)=0.1 and 
P(A and 
B)=0.041, determine the value of 
P(B), rounding to the nearest thousandth, if necessary.
Answer:

Given that events A and B are independent with P(A)=0.1 P(A)=0.1 and P(A P(A and B)=0.041 B)=0.041 , determine the value of P(B) P(B) , rounding to the nearest thousandth, if necessary.\newlineAnswer:

Full solution

Q. Given that events A and B are independent with P(A)=0.1 P(A)=0.1 and P(A P(A and B)=0.041 B)=0.041 , determine the value of P(B) P(B) , rounding to the nearest thousandth, if necessary.\newlineAnswer:
  1. Calculate Product: Since events AA and BB are independent, the probability of AA and BB occurring together, P(A and B)P(A \text{ and } B), is the product of their individual probabilities, P(A)×P(B)P(A) \times P(B).\newlineWe are given:\newlineP(A)=0.1P(A) = 0.1\newlineP(A and B)=0.041P(A \text{ and } B) = 0.041\newlineWe can express P(A and B)P(A \text{ and } B) as P(A)×P(B)P(A) \times P(B).\newlineSo, we have the equation:\newlineBB00
  2. Find P(B)P(B): To find P(B)P(B), we need to divide both sides of the equation by P(A)P(A).
    P(B)=P(A and B)P(A)P(B) = \frac{P(A \text{ and } B)}{P(A)}
    P(B)=0.0410.1P(B) = \frac{0.041}{0.1}
  3. Perform Division: Now we perform the division to find P(B)P(B). P(B)=0.0410.1P(B) = \frac{0.041}{0.1} P(B)=0.41P(B) = 0.41
  4. Correct Division: Correcting the division from the previous step:\newlineP(B) = 0.041/0.10.041 / 0.1\newlineP(B) = 0.410.41 (This was incorrect.)\newlineThe correct division is:\newlineP(B) = 0.041/0.10.041 / 0.1\newlineP(B) = 0.410.41 (This is still incorrect.)

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