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Given 
f(x)=-x^(2)-3x+20, find 
f(6)
Answer:

Given f(x)=x23x+20 f(x)=-x^{2}-3 x+20 , find f(6) f(6) \newlineAnswer:

Full solution

Q. Given f(x)=x23x+20 f(x)=-x^{2}-3 x+20 , find f(6) f(6) \newlineAnswer:
  1. Substitute value into function: Substitute the value 66 into the function f(x)f(x).f(6)=(6)23(6)+20f(6) = -(6)^2 - 3(6) + 20
  2. Calculate square of 66: Calculate the square of 66. (6)2=36(6)^2 = 36
  3. Multiply 33 by 66: Multiply 33 by 66.\newline3(6)=183(6) = 18
  4. Substitute values into function: Substitute the calculated values into the function. f(6)=3618+20f(6) = -36 - 18 + 20
  5. Perform arithmetic operations: Perform the arithmetic operations.\newlinef(6)=3618+20f(6) = -36 - 18 + 20\newlinef(6)=54+20f(6) = -54 + 20\newlinef(6)=34f(6) = -34

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