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Given:$\newline$$$\begin{array}{l} f(t)=t^{2}-10 t \\ h(t)=\frac{24}{t} \end{array}$$$\newline$Vince tried to evaluate $f(h(12))$, but he made a mistake. Here is his work.$\newline$Step $1 \quad f(12)=12^{2}-10(12)$$\newline$$$=24$$$\newline$Step $2$$\newline$$$\begin{aligned} h(24) & =\frac{24}{24} \\ & =1 \end{aligned}$$$\newline$Step $3 f(h(12))=1$$\newline$What is the mistake in Vince's work?