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Four students, Rahul, Mia, Mila, and Andres, line up one behind the other. How many different ways can they stand in line?
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Four students, Rahul, Mia, Mila, and Andres, line up one behind the other. How many different ways can they stand in line?\newlineAnswer:

Full solution

Q. Four students, Rahul, Mia, Mila, and Andres, line up one behind the other. How many different ways can they stand in line?\newlineAnswer:
  1. Identify nn: To determine the number of different ways the four students can stand in line, we need to calculate the number of permutations of the four individuals. A permutation is an arrangement of all members of a set into some sequence or order. Since there are no restrictions given, we can use the formula for permutations of nn distinct objects, which is n!n! (nn factorial), where nn is the number of objects to arrange.
  2. Calculate n!n!: First, we identify the value of nn, which is the number of students. There are 44 students: Rahul, Mia, Mila, and Andres. So, n=4n = 4.
  3. Find factorial of n: Next, we calculate the factorial of nn, which is 4!4! (44 factorial). The factorial of a number is the product of all positive integers less than or equal to that number. Therefore, 4!=4×3×2×14! = 4 \times 3 \times 2 \times 1.
  4. Perform multiplication: Now, we perform the multiplication to find the value of 4!4!. So, 4!=4×3×2×1=244! = 4 \times 3 \times 2 \times 1 = 24.
  5. Final result: The result of 2424 represents the total number of different ways the four students can stand in line.